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How many solutions does the equation have? 9z+10=1β3(5β3z) (a) 0(b) 1(c) infinitely many
5 months ago
Q:
How many solutions does the equation have? 9z+10=1β3(5β3z) (a) 0(b) 1(c) infinitely many
Accepted Solution
A:
9z + 10 = 1 - 3(5 - 3z)
9z + 10 = 1 - 15 + 9z
9z + 10 = 9z - 14
9z - 9z = -14 - 10
0 = - 24....incorrect
This equation has no solutions....0 solutions