MATH SOLVE

5 months ago

Q:
# How many solutions does the equation have? 9z+10=1β3(5β3z) (a) 0(b) 1(c) infinitely many

Accepted Solution

A:

9z + 10 = 1 - 3(5 - 3z)

9z + 10 = 1 - 15 + 9z

9z + 10 = 9z - 14

9z - 9z = -14 - 10

0 = - 24....incorrect

This equation has no solutions....0 solutions

9z + 10 = 1 - 15 + 9z

9z + 10 = 9z - 14

9z - 9z = -14 - 10

0 = - 24....incorrect

This equation has no solutions....0 solutions